Figure 1: Flow streamlines in a viscous fluid.
Now let's return to breakfast. I've got the honey on my spoon, and am fascinated by its slow-moving viscous behaviour. I lift the spoon high, and turn it upside down, watching for the honey to fall onto my toast. It takes a few seconds before it moves very much at all, but then it falls in a rush, as I now demonstrate.
Figure 2: Calculated shape of a drop of viscous fluid.Next I show a video of the same honey-falling flow. This video is not a close-up
of the actual demonstration, but is a computer simulation. It was prepared by my
PhD student
Yvonne Stokes,
using a `finite-element' program. This was actually
designed to be used with some industrial applications. Yvonne's main work is on the slumping of molten glass into a mould, which is
a very important process in the optical industry. Anyway, the computation is
clearly seen to be a very good model of actual flow of honey.
The final fall occurs
so rapidly that we need to split the screen; a compressed image allows more of the final fall to be seen. The previous picture shows a single frame from this video.
For the rest of this talk, I want to illustrate how very simple Year-12 level
calculus can throw some light on this sudden-fall phenomenon.
The next picture
shows a snapshot of the honey-drop during its fall. I am going to be daring
enough to ask you to appreciate some algebraic symbols, introducing the symbol
to denote the length of the drop. Also I will use the symbol
in the
obvious way to denote the time. The question is, how does length
vary with
time
?
measures population size, then the rate of
increase of
is proportional to the present value of
.
Malthus's law of
exponential population growth is a famous biological result meaning that the
population increases ``for ever''. Of course some other effect like food
limitation will eventually intervene to slow down this increase. Similarly, if
exponential growth really did apply to honey falling, the length
of the drop
would apparently increase for ever. Fortunately the toast eventually gets in
the way!
Every Year-12 mathematics student can (or should be able to!) solve the
differential equation for explosive growth.
It is actually a bit easier than that for exponential growth.
The answer is just that behaves like the
reciprocal of a time difference. The most important consequence is that there is a finite
time
at which
becomes infinite! This is the time when the explosion
actually happens, or the time when the honey really falls.
The previous picture shows a graph of
against
.
Even for exponential growth eventually becomes infinite,
but only if you wait an infinite time.
With explosive growth you don't have to wait an infinite time.
The same practical qualification prevents an actual infinite value
of
from occurring; namely, the honey hits the toast.
(Photograph by Austin Post, USGS; reproduced from the collection of images available at the Cascades Volcano Observatory.)
(Photograph by Peter W Lipman, USGS; from the Cascades Volcano Observatory.)
The dome on Mt St Helens, was growing at up to 1.5m per day.
From the technical point of view,
there is immense interest in the actual value of the explosion time .
If
was known for Mount St Helens, lives could have been saved.
Indeed, the earthquake prediction business is precisely about this
estimation.
For the honey drop, we can predict
quite well.
For example,
is proportional to the
viscosity of the
honey. Obviously thicker honey takes longer to fall.
This type of study is typical of Applied Mathematics.
Although the honey problem may seem rather trivial or silly,
I hope you can see the important practical generalisations,
some of which require only very elementary mathematics.